Import your CSS for SharePoint Themes

on Thursday, August 13, 2009


To Create a CustomSite Theme, Following Steps needs to be followed.

1. Create a Folder(CustomSiteTheme) inside 12\TEMPLATE\THEMES folder and put your css file and INF file inside this folder.
2. Add following entry into 12\TEMPLATE\LAYOUTS\1033\SPThemes.XML file.

<Templates>
<TemplateID>Zoro</TemplateID>
<DisplayName>Zoro</DisplayName>
<Description>Reflector theme</Description>
<Thumbnail>images/threflector.gif</Thumbnail>
<Preview>images/threflector.gif</Preview>
</Templates>
Apply the Theme and your changes will be seen in your site.


One of the major drawbacks of SharePoint themes is you have to reapply the theme to any site that uses your custom theme in order to see any new changes that you have made. This happens because when you apply a theme to a SharePoint site, a copy of the theme is added for the site in the content database.

Try it out, open a test site in SharePoint Designer and look at the folder structure in the Folder List task pane. If you have already applied a theme to this site, you will see a _theme folder. If you have not applied a theme to this site, then this folder will not appear. Expand the folder and you will see a single sub folder named the same as your theme. Now go and change the theme the site uses through a browser. Return to SharePoint Designer and hit F5 to refresh the Folder List. The _theme folder will appear if you didn't have a theme applied the first time, and the sub folder under this directory will change to reflect the theme you just applied.

When you make a change to the theme files on the web server, it does not update any copies of the theme that live in the content database. When you apply a new theme in the browser, it replaces the copy in the content database with a new theme. That is why you have to physically reapply a theme when you make changes, you have to replace the theme copy in the content database.

From a development perspective, the theme copy in the content database is rather handy. If you update any of the files in the content database (by changing the CSS files in SharePoint Designer and importing in new images), the changes automatically appear in the browser. Woo-hoo! This just made life easier when it comes to developing themes.

But after you finish up development, you are stuck back with the problem of how to update your theme in the future, especially if it is applied to several sites. This is where this trick comes in.
Import CSS to Create Editable Themes

Create a copy of the final theme.css file and store it in another location on the web server, such as:
C:\Program Files\Common Files\Microsoft Shared\web server extensions\12\TEMPLATE\LAYOUTS\1033\STYLES\YOURCUSTOMFOLDERHERE
You can even rename the file, it no longer needs to be named theme.css.

Open the original theme.css file in the custom theme folder, delete out all of the contents, and add an import rule for your new CSS file:
@import url("/_layouts/1033/styles/YOURCUSTOMFOLDERHERE/theme.css");

Save the file and deploy your theme (add text to SPTHEMES.xml and reset IIS). Apply your new theme to the site. Now go to the new CSS file in the Styles folder and make a change. Refresh your browser. Your change will appear. That is cool.

By moving around your files and using the import rule you can create a theme that you can update without reapplying the theme to every site that uses it. Be sure to update your image paths in your CSS styles to a location where you can edit the images as well, such as:
C:\Program Files\Common Files\Microsoft Shared\web server extensions\12\TEMPLATE\IMAGES\YOURCUSTOMFOLDERHERE

Never Use Index to get an SPListItem instead use GetItemByGuid


To read data from list we have to get reference to list first. SPWeb has lists collection we can use to find the list we are interested in. Following code example shows how to get instance of list.
--------------------------------------------------------------------------------
SPWeb web = SPContext.Current.Web;
SPList list = web.Lists["MyList"];
--------------------------------------------------------------------------------

List, as we can remember, is something like table and something like collection. List has its definition, fields collection and items collection. So, if we want to print out titles of all items in list we can iterate through items collections of list.


--------------------------------------------------------------------------------
private static void PrintItemTitles()
{
string strUrl = "http://localhost:8099/";
using (SPSite site = new SPSite(strUrl))
{
using (SPWeb web = site.OpenWeb())
{
SPList list = web.Lists["MyList"];
SPListItemCollection items = list.Items;
foreach (SPListItem item in items)
if (item != null)

Console.WriteLine(item.Title);
}
}
}
--------------------------------------------------------------------------------
To get item from list we have the following options:

•asking item directly from collection,
•asking item by id,
•querying list to get an item.
Asking item directly from items collection is very resource expensive. If you need one item from large list and you know its numeric ID or GUID then you should never ask item directly from collection. The reason is very simple - to get item from collection by its index then collection must be filled with items first. And if collection is filled you have suddenly all the list items in memory. It is not very nice surprise if list has about 50.000 documents.

--------------------------------------------------------------------------------
SPListItem item = list.Items[itemIndex];
--------------------------------------------------------------------------------
The other option is to get item by its ID. This is done by GetItemById() method.
--------------------------------------------------------------------------------
SPListItem item = list.GetItemById(itemIndex);
--------------------------------------------------------------------------------

If you know item GUID then you can use GetItemByUniqueId() method that works like previous one but uses GUID instead of numeric ID.

--------------------------------------------------------------------------------
SPListItem item = list.GetItemByUniqueId(itemGuid);
--------------------------------------------------------------------------------

These methods are not such resource eaters as asking the whole items collection. Behind the scenes it creates query that returns data only for list item with specified ID and if list item is found then it is constructed and returned.

NB! If you ask Items collection form list then every time all list items will be asked and constructed again. The results are not cached. If you use Items collection then ask it only once - like I did in the previous code example where item titles were printed to console.

I just mentioned querying and you may ask if you can do more with querying than just ask item from list by its ID. Of course, you can. You can query lists by different criterias and we will cover this in next blog entri in this serie.

Invoke Workflow Programmatically


Hi All,

Sometimes i wonder about the Workflow triggering technique from the List and Document Library. I wonder because of one observation.

Let me share it with you, when you attach the workflow to a list or document library we have an option to configure it that when to trigger, is it on adding of the new item or is it on Updating the item. Adding a new item is a one time job, so for this scenario, it looks perfect for me.

But, when i consider trigger when updating item, it is something that i do not think this is done properly.

Because Once you open the ListItem for edit, do not edit anything and press OK. What happens, Still Workflow Triggers.

Now the question is, is it really cool to trigger the workflow even if you have not made any changes???????? I do not think so...


So bottom line is to check the proper condition in code and then dynamically from code, trigger the workflow.

Here is a way to trigger the workflow from code.

First you need to take the SPWorkflowManager Object.


SPWorkflowManager objWorkflowManager = null;


Then use SPWorkflowAssociationCollection object. every List and Document library has association with the workflow, to get this we have to use this object to collect all workflows which are associated with the List or DocumentLibrary.

SPWorkflowAssociationCollection objWorkflowAssociationCollection = null;

I consider that i am using Event Handler, if you are using this code anywhere else, change the Web and Site objects accordingly.


We have WorkflowManager object at Site Level, so first we will take it.


objWorkflowManager = item.Web.Site.WorkflowManager;


Then we will take all association of the workflow for specific list.


objWorkflowAssociationCollection = item.ParentList.WorkflowAssociations;


Now consider a scenario, where you have multiple workflows associated with the same list or document library. So First we need to find the correct Workflow Association to trigger only that workflow.

So for that first Loop through all Associations,


foreach (SPWorkflowAssociation objWorkflowAssociation in objWorkflowAssociationCollection)

{
if (String.Compare(objWorkflowAssociation.BaseId.ToString("B"), {"Workflow_GUID"}, true) == 0)

{

//We found our workflow association that we want to trigger.

//Replace the workflow_GUID with the GUID of the workflow feature that you
//have deployed.

objWorkflowManager.StartWorkflow(item, objWorkflowAssociation, objWorkflowAssociation.AssociationData, true);
//The above line will start the workflow...
break;
}
}

Sample Code:



using (SPSite site = new SPSite("http://localhost:777/"))
{
using (SPWeb web = site.OpenWeb())
{
SPWorkflowManager manager = site.WorkflowManager;
SPList InvoiceList = web.Lists["Invoices"];
SPWorkflowAssociation helloWorldAssociation = null;
SPListItem item = InvoiceList.Items[0];
foreach (SPWorkflowAssociation association in InvoiceList.WorkflowAssociations)
{
if (association.BaseId == new Guid("64A0BC39-E987-4c39-9308-15F6511E8435"))
{
manager.StartWorkflow(item, association,"",true);
}
}
}
}

Clustered and NonClustered Index explained

on Wednesday, August 12, 2009






When I first started using SQL Server as a novice, I was initially confused as to the differences between clustered and non-clustered indexes. As a developer, and new DBA, I took it upon myself to learn everything I could about these index types, and when they should be used. This article is a result of my learning and experience, and explains the differences between clustered and non-clustered index data structures for the DBA or developer new to SQL Server. If you are new to SQL Server, I hope you find this article useful.



As you read this article, if you choose, you can cut and paste the code I have provided in order to more fully understand and appreciate the differences between clustered and non-clustered indexes.


 


Part I: Non-Clustered Index

Creating a Table

To better explain SQL Server non-clustered indexes; let’s start by creating a new table and populating it with some sample data using the following scripts. I assume you have a database you can use for this. If not, you will want to create one for these examples.


Create Table DummyTable1
(
EmpId Int,
EmpName Varchar(8000)
)


When you first create a new table, there is no index created by default. In technical terms, a table without an index is called a “heap”. We can confirm the fact that this new table doesn’t have an index by taking a look at the sysindexes system table, which contains one for this table with an of indid = 0. The sysindexes table, which exists in every database, tracks table and index information. “Indid” refers to Index ID, and is used to identify indexes. An indid of 0 means that a table does not have an index, and is stored by SQL Server as a heap.


Now let’s add a few records in this table using this script:



Insert Into DummyTable1 Values (4, Replicate ('d',2000))
GO


Insert Into DummyTable1 Values (6, Replicate ('f',2000))
GO


Insert Into DummyTable1 Values (1, Replicate ('a',2000))
GO


Insert Into DummyTable1 Values (3, Replicate ('c',2000))
GO


Now, let’s view the contests of the table by executing the following command in Query Analyzer for our new table.


Select EmpID From DummyTable1
GO
















Empid


4


6


1


3


As you would expect, the data we inserted earlier has been displayed. Note that the order of the results is in the same order that I inserted them in, which is in no order at all.


Now, let’s execute the following commands to display the actual page information for the table we created and is now stored in SQL Server.


dbcc ind(dbid, tabid, -1) – This is an undocumented command.


DBCC TRACEON (3604)
GO


Declare @DBID Int, @TableID Int
Select @DBID = db_id(), @TableID = object_id('DummyTable1')


DBCC ind(@DBID, @TableID, -1)
GO



This script will display many columns, but we are only interested in three of them, as shown below.






















PagePID


IndexID


PageType


26408


0


10


26255


0


1


26409


0


1


Here’s what the information displayed means:


PagePID is the physical page numbers used to store the table. In this case, three pages are currently used to store the data.


IndexID is the type of index,


Where:




0 – Datapage


1 – Clustered Index


2 – Greater and equal to 2 is an Index page (Non-Clustered Index and ordinary index),


PageType tells you what kind of data is stored in each database,


Where:



10 – IAM (Index Allocation MAP)


1 – Datapage


2 – Index page



Now, let us execute DBCC PAGE command. This is an undocumented command.


DBCC page(dbid, fileno, pageno, option)


Where:



dbid = database id.


Fileno = fileno of the page.  Usually it will be 1, unless we use more than one file for a database.


Pageno = we can take the output of the dbcc ind page no.


Option = it can be 0, 1, 2, 3. I use 3 to get a display of the data.  You can try yourself for the other options.



Run this script to execute the command:


DBCC TRACEON (3604)
GO


DBCC page(@DBID, 1, 26408, 3)
GO


The output will be page allocation details.


DBCC TRACEON (3604)
GO


dbcc page(@DBID, 1, 26255, 3)
GO




The data will be displayed in the order it was entered in the table. This is how SQL stores the data in pages.  Actually, 26255 & 26409 both display the data page.


I have displayed the data page information for page 26255 only. This is how MS SQL stores the contents in data pages as such column name with its respective value.  


Record Type = PRIMARY_RECORD                        


EmpId          = 4


EmpName    = ddddddddddddddddddddddddddddddddddddddddddddddddddd
ddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
ddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
ddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
ddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd



 


Record Type = PRIMARY_RECORD                       


EmpId            = 6


EmpName      = ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff


 


Record Type = PRIMARY_RECORD                       



EmpId           = 1


EmpName     = aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa


 


This displays the exact data storage in SQL, without any index on table. Now, let’s go and create a unique non-clustered index on the EmpID column.


 


Creating a Non-Clustered Index


Now, we will create a unique non-clustered index on the empid column to see how it affects the data, and how the data is stored in SQL Server.



CREATE UNIQUE NONCLUSTERED INDEX DummyTable1_empid
ON DummyTable1 (empid)
GO


Now, execute the DBCC ind (dbid, tabid, -1)


DBCC TRACEON (3604)
GO


Declare @DBID Int, @TableID Int
Select @DBID = db_id(), @TableID = object_id('DummyTable1')
DBCC ind(@DBID, @TableID, -1)
GO


Here are the results:
































PagePID


IndexID


PageType


26408


0


10


26255


0


1


26409


0


1


26411


2


10


26410


2


2


Now, we see two more rows than before, which now contains index page details. Page 26408 displays the page allocation details, and pages 26255 and 26409 display the data page details, as before.


In regard to the new pages, page 26411 displays the page allocation details of an index page and page 26410 displays the index page details.


MS SQL generates a page (pagetype = 10) for an index and explains the page allocation details for an index. It shows the number of index page have been occupied for an index.


Let us see what would be the output for page 26411, that is page type = 10



 


IAM: Single Page Allocations @0x308A608E


-----------------------------------------


Slot 0 = (1:26410)


 


Let us view page 26410 to see the index page details.


DBCC TRACEON (3604)
GO


DBCC page(10, 1, 26410, 3)
GO


SQL populates the index column data in order. The last column (?) is pointed to the row locator.



Here are the results, using two different methods:

Method I




























FileID


PageID


EMPID



?


1


26410


1


0x8F66000001000200



1


26410


3


0x2967000001000000


1


26410


4


0x8F66000001000000


1


26410


6



0x8F66000001000100


The row location display in one of two ways:



  • If the table does not have a clustered index, the row locator will be combination of fileno, pageno and the no of rows in a page. 

  • If the table does have clustered index, the row location will be clustered index key value.

Non-clustered indexes are particularly handy when we want to return a single row from a table.


For example, to search for employee ID (empid = 3) in a table that has a non-clustered index on the empid column, SQL Server looks through the index to find an entry that lists the exact page and row in the table where the matching empid can be found, and then goes directly to that page and row. This greatly speeds up accessing the record in question.


Select EmpID, EmpName From DummyTable1 WHERE EMPID = 3


Now, let’s insert some more rows in our table and view the data page storage of our non-clustered index.



Insert Into DummyTable1 Values (10, Replicate ('j',2000))
GO

Insert Into DummyTable1 Values (2, Replicate ('b',2000))
GO


Insert Into DummyTable1 Values (5, Replicate ('e',2000))
GO


Insert Into DummyTable1 Values (8, Replicate ('h',2000))
GO


Insert Into DummyTable1 Values (9, Replicate ('i',2000))
GO


Insert Into DummyTable1 Values (7, Replicate ('g',2000))
GO



Now, let’s view the data in our table.



Execute:


Select EmpID From DummyTable1


Here are the results:



























EmpID


4


6


1


3


10



2


5


8


9


7



As you may notice above, the data is still in the order we entered it, and not in any particular order. This is because adding the non-clustered index didn’t change how the data was stored and ordered on the data pages.


Now, let’s view the results of the DBCC IND command. In order to find out what happened when the new data was added to the table.


DBCC TRACEON (3604)
GO


Declare @DBID Int, @TableID Int
Select @DBID = db_id(), @TableID = object_id('DummyTable1')
DBCC ind(@DBID, @TableID, -1)
GO


Here are the results:






































PagePID


IndexID


PageType


26408


0



10


26255


0


1


26409



0


1


26412


0


1



26413


0


1


26411


2


10


26410


2


2


Let us execute the page 26410 again and get the index page details.


DBCC TRACEON (3604)
GO


dbcc page(10, 1, 26410, 3)
GO



SQL Server populates the index column data in order.  The last column (?) is pointed to the row locator.


Here are the results:


Method I
































































FileID



PageID


EMPID


?


1


26410


1


0x8F66000001000200


1


26410


2


0x2C67000001000000


1


26410


3


0x2967000001000000


1



26410


4


0x8F66000001000000


1


26410


5


0x2C67000001000100


1


26410


6


0x8F66000001000100


1


26410


7


0x2D67000001000000


1



26410


8


0x2C67000001000200


1


26410


9


0x2967000001000200


1


26410


10


0x2967000001000100


As I explained earlier, there are two types of row locations. We have seen Method I.  Now, let’s try Method II with the help of a clustered and non-clustered index in a table. DummyTable1 already has a non-clustered index. Let’s now add a new column to the DummyTabl1 table and add a clustered index on that column. 



Alter Table DummyTable1 Add EmpIndex Int IDENTITY(1,1)
GO


This will link the clustered index key value, instead of the row locator, and be will the combination of fileno, pageno and no of rows in a page. 


This adds the Empindex column to DummyTable1. I have used an identity column so that we will not have null values on that column.


You can execute the DBCC ind and DBCC page to check if there any change after the new column is added to the table. If you don’t want to check this yourself, I can tell you that adding the new column did not affect the total number of pages currently allocated to the table by SQL Server.


Now, let’s add a unique clustered index on the empindex column and then view the differences in page 26410.


First, we execute the DBCC ind command.  This displays a new set of pages for dummytable1.



DBCC TRACEON (3604)
GO


Declare @DBID Int, @TableID Int
Select @DBID = db_id(), @TableID = object_id('DummyTable1')
DBCC ind(@DBID, @TableID, -1)
GO


Here are the results:







































PagePID



IndexID


PageType


26415


1


10



26414


0


1


26416


1


2


26417


0


1


26418


0


1


26420


2


10


26419


2


2


Pages 26415 and 26420 have page allocation details.  Pages 26414, 26417 and 26418 have data page details.


Now, let’s view pages 26416 and 26419 and see the output.


DBCC TRACEON (3604)
GO


DBCC page(10, 1, 26416, 3)
GO



Here are the results:


























FileID


PageID


ChildPageID


EMPID


1


26416


26414


0


1


26416


26417


5


1


26416



26418


9


This displays the output of the clustered index page, which has got a link to data page (ChildPageID).  EMPID is an index column that contains the starting row of the page.


DBCC TRACEON (3604)
GO


DBCC page(10, 1, 26419, 3)
GO


Here are the results:



Method II

































































FileID


PageID


EMPID


EMPIndex


1


26419


1


1


1


26419


2


2


1


26419



3


3


1


26419


4


4


1


26419


5


5


1


26419


6


6


1


26419



7


7


1


26419


8


8


1


26419


9


9


1


26419


10


10


It is interesting to see the differences now. There is a difference between Method I and Method IIMethod II is now linked to a clustered index key.



The main difference between Method I and Method II is the link to a row in a data page.


 


Part II: Clustered Index


Creating a Table


To better explain how SQL Server creates clustered indexes; let’s start by creating a new table and populating it with some sample data using the following scripts. You can use the same sample database as before.


Create Table DummyTable2



(
    EmpId Int,
    EmpName Varchar(8000)
)


As in the previous example, when you first create a new table, there is no index created by default, and a heap is created. As before, we can confirm the fact that this new table doesn’t have an index by taking a look at the sysindexes system table, which contains one for this table with an of indid = 0. The sysindexes table, which exists in every database, tracks table and index information. “Indid” refers to Index ID, and is used to identify indexes. An indid of 0 means that a table does not have an index, and is stored by SQL Server as a heap.


Now let’s add a few records in this table using this script:


Insert Into DummyTable2 Values (4, Replicate ('d',2000))
GO


Insert Into DummyTable2 Values (6, Replicate ('f',2000))
GO


Insert Into DummyTable2 Values (1, Replicate ('a',2000))
GO



Insert Into DummyTable2 Values (3, Replicate ('c',2000))
GO


Now, let’s view the contents of the table by executing the following command in Query Analyzer for our new table.


Select EmpID From DummyTable2
GO















Empid


4


6


1


3


As you would expect, the data we inserted has been displayed. Note that the order of the results is in the same order that I inserted them in, which is in no order at all.


Now, let’s execute the following commands to display the actual page information for the table we created and is now stored in SQL Server.


DBCC ind(dbid, tabid, -1) – It is an undocumented command. 



DBCC TRACEON (3604)
GO


Declare @DBID Int, @TableID Int
Select @DBID = db_id(), @TableID = object_id('DummyTable2')
DBCC ind(@DBID, @TableID, -1)
GO


This script will display many columns, but we are only interested in three of them, as shown below.


Here are the results:






















PagePID


IndexID


PageType


26408


0


10


26255


0


1


26409


0



1


Here’s what the information displayed means:


PagePID is the physical page numbers used to store the table. In this case, three pages are currently used to store the data.


IndexID is the type of index,


Where:



0 – Datapage


1 – Clustered Index


2 – Greater and equal to 2 is an Index page (Non-Clustered Index and ordinary index)



PageType tells you what kind of data is stored in each database


Where:



10 – IAM (Index Allocation MAP)


1 – Datapage


2 – Index page


Now, let us execute DBCC PAGE command.


DBCC page(dbid, fileno, pageno, option)


Where:




dbid = database id.


Fileno = fileno of the page.  Usually it will be 1, unless we use more than one file for a database.


Pageno = we can take the output of the dbcc ind page no.


Option = it can be 0, 1, 2, 3. I use 3 to get a display of the data.  You can try yourself for the other options.


Run this script to execute the command:


DBCC TRACEON (3604)
GO



DBCC page(@DBID, 1, 26408, 3)
GO


The output will be page allocation details.


DBCC TRACEON (3604)
GO


DBCC page(@DBID, 1, 26255, 3)
GO



The output will display the data however it was entered in the table. This is how SQL stores the data in pages. Actually, 26255 & 26409 will display the data page.


I have displayed the data page information for page 26255 only. This is how MS-SQL stores the contents in data pages as such column name with its respective value.  


 


Record Type = PRIMARY_RECORD                       


EmpId          = 4


EmpName    = dddddddddddddddddddddddddddddddddddddddddddddddd
dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd



 


Record Type = PRIMARY_RECORD                       


EmpId           = 6


EmpName     = ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
fffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
fffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff


 


Record Type = PRIMARY_RECORD                       


EmpId           = 1



EmpName     = aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa


This displays the exact data storage in SQL without any index on table. Now, let’s go and create a Unique Clustered Index on EmpID column.


 


Create a Clustered Index


Now, let us create a unique clustered index on empid column to see how it affects the data that is stored in SQL Server.


CREATE UNIQUE CLUSTERED INDEX DummyTable2_EmpIndex
ON DummyTable2 (EmpID)
GO



Execute:


Select EmpID From DummyTable2


Here are the results:















Empid


1


3


4


6


Now, execute the DBCC ind (dbid, tabid, -1)


DBCC TRACEON (3604)
GO


Declare @DBID Int, @TableID Int



Select @DBID = db_id(), @TableID = object_id('DummyTable2')


DBCC ind(@DBID, @TableID, -1)
GO


Here are the results:




















PagePID


IndexID



PageType


26411


1


10


26410



0


1


26412


1


2


 MS SQL generates a page (pagetype = 10) for an index and explains the page allocation details for an index. It shows the number of index page have been occupied for an index.



Now, let us view the page 26410 and 26412 and see the page details.


DBCC TRACEON (3604)
GO


DBCC page(10, 1, 26412, 3)
GO


Here are the results:















FileID



PageID


ChildPageID


EMPID


1


26412


26410


0


 


The output display many columns, but we are only interested in four of them as shown above.


This will display the output of the index page, which has got link to data page (ChildPageID).  EMPID is an index column will contain the starting row of the page.


Now, let us view the page 26410 and see the page details. 


DBCC TRACEON (3604)
GO


DBCC page (10, 1, 26410, 3)
GO



Here are the results:


 


Record Type = PRIMARY_RECORD     


EmpId            = 1


EmpName          = aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa



 


Record Type = PRIMARY_RECORD     


EmpId            = 2


EmpName          = bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb


 



Record Type = PRIMARY_RECORD     


EmpId            = 3


EmpName          = cccccccccccccccccccccccccccccccccccccccccccccccc
cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc


Though I have added disorder records, SQL has displayed the data page in sequence because we have got a clustered index on empid. This is absolutely great!  Adding a clustered index to the table has physically reordered the data pages, putting them in physical order based on the indexed column.



Now, let’s insert some more rows in our table and view the data and index page storage of our clustered index.

Insert Into DummyTable2 Values (10, Replicate ('j',2000))
GO

Insert Into DummyTable2 Values (2, Replicate ('b',2000))
GO

Insert Into DummyTable2 Values (5, Replicate ('e',2000))
GO

Insert Into DummyTable2 Values (8, Replicate ('h',2000))
GO

Insert Into DummyTable2 Values (9, Replicate ('i',2000))
GO

Insert Into DummyTable2 Values (7, Replicate ('g',2000))
GO

Now, execute the DBCC ind (dbid, tabid, -1)

DBCC TRACEON (3604)
GO

Declare @DBID Int, @TableID Int

Select @DBID = db_id(), @TableID = object_id('DummyTable2')

DBCC ind(@DBID, @TableID, -1)
GO

Here are the results:

PagePID


IndexID


PageType

26411


1


10

26410


0


1

26412


1


2

26255


0


1

26408


0


1

26409


0


1

Now, we see few more rows than before. Page 26411 displays the page allocation details, and pages 26408, 26409, 26410 and 26255 display the data page details, as before.

In regard to the new pages, page 26411 displays the page allocation details of an index page and 26412 displays the index page details.

MS-SQL generates a page (pagetype = 10) for an index and explains the page allocation details for an index. It shows the number of index page have been occupied for an index.

Let us see what would be the output for page 26411, that is page type = 10.

DBCC TRACEON (3604)
GO

dbcc page(10, 1, 26411, 3)
GO

Here are the results:

IAM: Single Page Allocations @0x30A5C08E

-----------------------------------------

Slot 0 = (1:26410)

Slot 1 = (1:26412)

Slot 2 = (1:26255)

Slot 3 = (1:26408)

Slot 4 = (1:26409)

Let us view page 26412 to see the index page details.

DBCC TRACEON (3604)
GO

DBCC page(10, 1, 26412, 3)
GO

Here are the results:

FileID


PageID


ChildPageID


EMPID

1


26412


26410


0

1


26412


26408


4

1


26412


26255


6

1


26412


26409


9

This helps us to get an idea to decide the need of clustered index. It is really useful to have a clustered index when retrieve many rows of data, ranges of data, and when BETWEEN is used in the WHERE clause. Because, the leaf level of the clustered index is the data. It should be used to save many I/Os. So, it is better to use clustered indexes to solve queries asking for ranges of data, not one row.

For example, to search for an employee ID (empid between 3 and 9) in a table that has a clustered index on the empid column.

Select EmpID, EmpName From DummyTable1 WHEREEMPID Between 3 And 9

Create Custom Sharepoint Timer Job and execute it.

on Tuesday, August 11, 2009


using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Microsoft.SharePoint.Administration;
using Microsoft.SharePoint;
using System.IO;

namespace SampleTimerJob
{
public class TaskCreatorJob :SPJobDefinition
{
public TaskCreatorJob()
: base()
{
}
public TaskCreatorJob(string jobName, SPService service, SPServer server, SPJobLockType targetType)
: base(jobName, service, server, targetType)
{

}

public TaskCreatorJob(string jobName, SPWebApplication webApplication)

: base(jobName, webApplication, null, SPJobLockType.ContentDatabase)
{
this.Title = "Task Logger";
}

public override void Execute(Guid targetInstanceId)
{
Console.WriteLine("Job is executing"+ DateTime.Now.ToLongDateString());
SPWebApplication webApplication = this.Parent as SPWebApplication;
SPContentDatabase db = webApplication.ContentDatabases[targetInstanceId];
SPDocumentLibrary docLib =db.Sites[0].RootWeb.Lists["Invoices"] as SPDocumentLibrary;
byte[] bytes=File.ReadAllBytes("c:\\logs.txt");
SPListItem item = db.Sites[0].RootWeb.Files.Add(docLib.RootFolder.Url + "/" + DateTime.Now.ToString("ddMMyyyyhhmmss"), bytes, true).Item;
item["Title"] = DateTime.Now.ToString();
item.Update();
//taskItem.Update();

//SPWebApplication webApplication = this.Parent as SPWebApplication;
//SPContentDatabase db = webApplication.ContentDatabases[targetInstanceId];
//SPList taskList = db.Sites[0].RootWeb.Lists["Tasks"];
//SPListItem taskItem = taskList.Items.Add();
//taskItem["Title"] = DateTime.Now.ToString();
//taskItem.Update();
//taskItem.Update();
base.Execute(targetInstanceId);
}
}
}




Execute it Programmatically

SPSite site = new SPSite("http://ramittalw09:777/");
//SPJobDefinition jobDef = site.WebApplication.JobDefinitions["TaskLogger"];
foreach (SPJobDefinition jobDef in site.WebApplication.JobDefinitions)
{
if (jobDef != null && jobDef.Name == "TaskLogger")
{
jobDef.Execute(site.ContentDatabase.Id);
break;
}
}